WAEC - Physics (2005 - No. 36)
a chemical cell of internal resistance 1\(\Omega\) supplies electric current to an external resistor of resistance 3\(\Omega\). Calculate the efficiency of the cell
75%
50%
33%
25%
Explication
R = \(r_1 + R = 1 + 3 = 4\Omega\)
\(\frac{3}{4} \times \frac{100}{1} = 75\)%
\(\frac{3}{4} \times \frac{100}{1} = 75\)%