WAEC - Physics (2005 - No. 33)
Two capacitors if capacitance 0.4\(\mu F\) and 0.5\(\mu F\) are connected in parallel and charged to a p.d. of 50V, Determine the total charge acquired
45\(\mu C\)
25\(\mu C\)
20\(\mu C\)
10\(\mu C\)
Explication
C = \(C_1 + C_2\) = 0.4 + 0.5 = 0.9\(\mu F\)
Q = Cv = 0.9 x 50 = 45\(\mu C\)
Q = Cv = 0.9 x 50 = 45\(\mu C\)