WAEC - Physics (2003 - No. 31)
Two identical cells each of e.m.f 2v and internal resistance 1.0\(\Omega\) are connected in parallel. The combination is connected to an external load of 1.5\(\Omega\). Calculate the current in the circuit
0.57A
1.00A
1.14A
2.00A
Explication
I = \(\frac{E}{R + r} = \frac{2}{1.5 + 0.5}\)
= 1A
= 1A