Se connecter
WAEC - Physics (2003 - No. 2)
A piece of metal of relative density 5.0 weighs 60N in air. Calculate its weight when fully immersed in water
4N
5N
48N
60N
Explication
R.D = \(\frac{m}{m - m_2} = 5 = \frac{60}{60 - m_1} = \frac{240}{5} = 48N\)
Commentaires (0)
Connectez-vous pour commenter
Publicité
Autoriser javascript à charger correctement cette page
