WAEC - Physics (2002 - No. 3)
A solid weight 45N and 15N respectively in air and water. Determine the relative density of the solid
0.33
0.50
1.50
3.00
Explication
R.d = \(\frac{\text{weight in air}}{\text{apparent loss of weight in water}} = \frac{45}{45 - 15}\)
= \(\frac{45}{30} = 1.50\)
= \(\frac{45}{30} = 1.50\)