WAEC - Physics (2002 - No. 28)
A converging lens of focal length 15cm forms a virtual image at a point 10cm from the lens. Calculate the distance of the object from the lens
10.00cm
6.00cm
5.00cm
1.50cm
Explication
\(\frac{1}{u} + \frac{1}{v} = \frac{1}{f} = \frac{1}{15} + \frac{1}{10}\)
u = 6.00
u = 6.00