WAEC - Physics (2002 - No. 12)
A spiral spring of natural length 30.0cm and force constant of 20Nm-1 is compressed to 20.0cm. Calculate the energy stored in the spring
0.1J
1.0J
10.0J
100.0J
Explication
Energy = \(\frac{1}{2} ke^2 = \frac{1}{2} \times 20 \times 0.1^2\)
= 0.1J
= 0.1J