WAEC - Physics (1997 - No. 29)
The current in the primary coil of a transformer is 2.5A. If the coil has 50 turns and the secondary250 turns, calculate the current in the secondary coil. Neglect energy losses in the transformer
0.2A
0.5A
2.5A
5A
12.5A
Explication
\(\frac{I_s}{I_p}=\frac{n_p}{n_s}, I_s= \frac{I_pn_p}{n_s}=\frac{2.5\times50}{250}\Rightarrow0.5A\)