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WAEC - Physics (1991 - No. 14)
The set-up illustrated above shows a capillary tube of uniform cross-sectional area in two different arrangements. Using the data in the diagrams. Calculate the pressure of the atmosphere
76cm of Hg
75cm of Hg
74cm of Hg
60cm of Hg
45cm of Hg
Explication
P
1
= p + 15, p
2
= p - 15
v
1
= 30cm, v
2
= 45cm
P
1
v
1
= p
2
v
2
p = 75cm of Hg
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