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WAEC - Mathematics (1995 - No. 35)
In the diagram above, AB//CD, the bisector of ∠BAC and ∠ACD meet at E. Find the value of ∠AEC
30
o
45
o
60
o
75
o
90
o
Explication
Ae is a bisector of BAC => EAC = 45
o
CE is the bisector of ACD => ACE = 45
o
AEC = 180
o
- [EAC + ACE]
= 180
o
- (45
o
+ 45
o
) = 180
o
- 90
o
= 90
o
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