WAEC - Chemistry (2015 - No. 22)
Consider the following reaction equation:
SO42-(aq) + 2H+(aq) + ye- \(\to\) SO42-(aq) + H2O(1).
The value of y in the equation is
SO42-(aq) + 2H+(aq) + ye- \(\to\) SO42-(aq) + H2O(1).
The value of y in the equation is
2
3
4
6
Explication
from the reaction, the total charge on the left side = The total charge on the right side
-2 + 2 + y = -2 : y = -2 : y = 2
-2 + 2 + y = -2 : y = -2 : y = 2