JEE MAIN - Physics (2004 - No. 4)
A radiation of energy $$E$$ falls normally on a perfectly reflecting surface. The momentum transferred to the surface is
$$Ec$$
$$2E/c$$
$$E/c$$
$$E/{c^2}$$
Explication
Momentum of photon $$ = {E \over c}$$
Change in momentum $$ = {{2E} \over c}$$
$$=$$ momentum transferred to the surface
(the photon will reflect with same magnitude of momentum in opposite direction)
Change in momentum $$ = {{2E} \over c}$$
$$=$$ momentum transferred to the surface
(the photon will reflect with same magnitude of momentum in opposite direction)