JEE MAIN - Physics (2004 - No. 31)
In an $$LCR$$ series $$a.c.$$ circuit, the voltage across each of the components, $$L,C$$ and $$R$$ is $$50V$$. The voltage across the $$L.C$$ combination will be :
$$100V$$
$$50\sqrt 2 $$
$$50$$ $$V$$
$$0$$ $$V$$ (zero)
Explication
Since the phase difference between $$L$$ & $$C$$ is $$\pi ,$$
$$\therefore$$ net voltage difference across $$LC=50-50=0$$
$$\therefore$$ net voltage difference across $$LC=50-50=0$$