JEE MAIN - Physics (2002 - No. 46)
When temperature increases, the frequency of a tuning fork
increases
decreases
remains same
increases or decreases depending on the material
Explication
KEY CONCEPT : The frequency of a tuning fork is given by the expression
$$f = {{{m^2}k} \over {4\sqrt 3 \pi {\ell ^2}}}\sqrt {{Y \over \rho }} $$
As temperature increases, $$\ell $$ increases and therefore $$f$$ decreases.
$$f = {{{m^2}k} \over {4\sqrt 3 \pi {\ell ^2}}}\sqrt {{Y \over \rho }} $$
As temperature increases, $$\ell $$ increases and therefore $$f$$ decreases.