JEE MAIN - Physics (2002 - No. 26)
Capacitance (in $$F$$) of a spherical conductor with radius $$1$$ $$m$$ is
$$1.1 \times {10^{ - 10}}$$
$${10^{ - 6}}$$
$$9 \times {10^{ - 9}}$$
$${10^{ - 3}}$$
Explication
For an isolated sphere, the capacitance is given by
$$C = 4\pi \,{ \in _0}\,r$$
$$ = {1 \over {9 \times {{10}^9}}} \times 1$$
$$ = 1.1 \times {10^{ - 10}}F$$
$$C = 4\pi \,{ \in _0}\,r$$
$$ = {1 \over {9 \times {{10}^9}}} \times 1$$
$$ = 1.1 \times {10^{ - 10}}F$$