JEE MAIN - Chemistry (2005 - No. 44)
The oxidation state of Cr in [Cr(NH3)4Cl2]+ is :
+3
+2
+1
0
Explication
Oxidation state of $$Cr$$ in $${\left[ {Cr{{\left( {N{H_3}} \right)}_4}C{l_2}} \right]^ + }.$$
Let it be $$x,\,\,1 \times x + 4 \times 0 + 2 \times \left( { - 1} \right) = 1$$
Therefore $$\,\,\,$$ $$x=3.$$
Let it be $$x,\,\,1 \times x + 4 \times 0 + 2 \times \left( { - 1} \right) = 1$$
Therefore $$\,\,\,$$ $$x=3.$$