JAMB - Physics (2025 - No. 56)
What pressure would a 5000N weight of water exert at the bottom of a reservoir containing it if its length and breadth are 10m and 5m, respectively
200Pa
182Pa
100Pa
120Pa
Explication
The pressure exerted by the water at the bottom of the reservoir is given by:
\(P = \frac{F}{A}\)
Given: \( F = 5000 \, \text{N} \) (weight of water), \( L = 10 \, \text{m} \) (length), \( B = 5 \, \text{m} \) (breadth)
Calculate the area \( A \):
\(A = L \times B = 10 \, \text{m} \times 5 \, \text{m} = 50 \, \text{m}^2\)
Calculate the pressure \( P \):
\(P = \frac{F}{A} = \frac{5000 \, \text{N}}{50 \, \text{m}^2} = 100 \, \text{Pa}\)