JAMB - Physics (2025 - No. 32)
What magnitude of electric current can store 2.5 J of energy in a 3 H induction coil?
1.29 A
2.48 A
5.00 A
3.66 A
Explication
Answer: A
Energy in an inductor: E = \(\frac{1}{2}\)LI\(^2\) ⇒ I ≈ 1.29 A.
Answer: A
Energy in an inductor: E = \(\frac{1}{2}\)LI\(^2\) ⇒ I ≈ 1.29 A.