JAMB - Physics (2018 - No. 75)
The efficiency of energy conversion on the energy flow through a hydroelectric power is?
\(\frac{E1}{E2}\)
\(\frac{E3}{E2}\)
\(\frac{E2}{E1}\)+ E2
\(\frac{E2}{E3}\) + E1
Explication
Efficiency = \(\frac{\text{useful energy output from machine}}{\text{energy input into machine}}\)
= \(\frac{E3}{E2}\)