JAMB - Physics (2010 - No. 7)
In a hydraulic press, the pump piston exerts a pressure of 100 pa on the liquid. what force is exerted in the second piston of cross sectional area 3 m2?
300 N
200 N
150 N
100 N
Explication
Thrust = pressure x area = 100 pa x 3 m2 = 300 N