JAMB - Physics (2008 - No. 9)
A spring of force constant 500 NM-1 is compressed such that its length shortens by 5cm. The energy stored in the spring is?
0.625 J
6.250 J
62.500 J
625.000 J
Explication
Energy stored in a spring = (1)/2 K e2 = (1)/2 x 500(0.05)2 = 0.625J