JAMB - Physics (2006 - No. 37)
The wavelength of the first overtone of a note in a closed pipe of length 33 cm is?
33 cm
44 cm
22 cm
17 cm
Explication
In a closed tube, the fundamental note occurs when the length of the tube l = \(\frac{λ}{4}\),
the first overtone occurs when the length of the tube l = \(\frac{3 \lambda}{4}\)
λ = \(\frac{4l}{3}\) = \(\frac{ 4 \times 33}{3}\) = 44 cm
the first overtone occurs when the length of the tube l = \(\frac{3 \lambda}{4}\)
λ = \(\frac{4l}{3}\) = \(\frac{ 4 \times 33}{3}\) = 44 cm