JAMB - Physics (1997 - No. 33)
In a meter bridge experiment, two resistor 2\(\Omega\) and 3\(\Omega\) occupy the left and right gaps respectively. Find the balance point from the left side of the bridge
20cm
40cm
60cm
80cm
Explication
Let the point be x
\(\frac{2}{x}\) = \(\frac{3}{100 - x}\)
making x subject of formula,
2(100 - x) = 3x
200 - 2x = 3x
200 = 3x + 2x
200 = 5x
divide both side by 5
x = 40cm
\(\frac{2}{x}\) = \(\frac{3}{100 - x}\)
making x subject of formula,
2(100 - x) = 3x
200 - 2x = 3x
200 = 3x + 2x
200 = 5x
divide both side by 5
x = 40cm