JAMB - Physics (1993 - No. 15)
Determine the distance between the consecutive antinodes XX if the wavelength is 60cm
15cm
30cm
60cm
120cm
Explication
Distance XX = \(\frac{1}{2}\)\(\lambda\)
= \(\frac{1}{2}\) x \(\frac{60}{1}\)
= 30cm
= \(\frac{1}{2}\) x \(\frac{60}{1}\)
= 30cm