JAMB - Physics (1992 - No. 10)
A platinum resistance thermometer wire has a resistance of 5 ohms at 0oC and 5.5 ohms at 100oC. Calculate the temperature of the wire when the resistance is 5.2 ohms
80oC
60oC
40oC
10oC
Explication
100oC .... 5.5
\(\theta\)oC .... 5.3
0oC .... 5.0
\(\frac{\theta - 0}{100 - 0}\) = \(\frac{5.5 - 5 .0}{5.5 - 5.0}\)
\(\theta\) = 40oC
\(\theta\)oC .... 5.3
0oC .... 5.0
\(\frac{\theta - 0}{100 - 0}\) = \(\frac{5.5 - 5 .0}{5.5 - 5.0}\)
\(\theta\) = 40oC