JAMB - Physics (1989 - No. 3)
Two points on a velocity time-graph have coordinates (5s, 10ms-1) and (20s, 20ms-1). Calculate the mean acceleration between the two points
0.67ms-1
0.83ms-1
1.50ms-1
2.00ms-1
Explication
a = \(\frac{v - u}{\Delta t}\)
a = \(\frac{20 - 10}{20 - 5}\)
a = 0.67ms-1
a = \(\frac{20 - 10}{20 - 5}\)
a = 0.67ms-1