JAMB - Physics (1985 - No. 17)
Two liquids, P at a temperature of 20oC and Q at a temperature of 80oC have specific heat capacities of 1.0Jkg-1oC-1 and 1.5J kg-1 oC-1respectively. if equal masses of P and Q are mixed in a lagged calorimeter, then the equilibrium temperature is
44oC
50oC
56oC
60oC
70oC
Explication
Heat lost = heat gained
m x (80 - \(\theta\)) x 1.5 = m x (\(\theta\) - 20) x 1
\(\theta\) = 56oC
m x (80 - \(\theta\)) x 1.5 = m x (\(\theta\) - 20) x 1
\(\theta\) = 56oC