JAMB - Physics (1982 - No. 18)
If the refractive index of a medium is \(\sqrt{2}\), what is the critical angle?
45o
50o12'
56o25'
75o
90o
Explication
sin C = \(\frac{1}{n}\) ; sin C = \(\frac{1}{√2}\)
C = sin-1\(\frac{1}{√2}\)
= 45o
C = sin-1\(\frac{1}{√2}\)
= 45o