JAMB - Physics (1981 - No. 37)
The extension in a spring when 5g wt was hung from it was 0.56cm. If Hooke's law is obeyed, What is the extension caused by a load of 20g wt?
1.12m
2.14cm
2.52cm
2.80cm
2.24cm
Explication
Extension & Load
Extension = K constant
\(\frac{\text{load}}{0.56cm}\) = \(\frac{X}{20g}\)
X = 2.24cm
Extension = K constant
\(\frac{\text{load}}{0.56cm}\) = \(\frac{X}{20g}\)
X = 2.24cm