JAMB - Physics (1980 - No. 17)
What is the relative permitivity of a capacitor if its capacitance with a medium as dielectric is 16 farads and its capacitance with vacuum as dielectric is 2 farads?
o
\(\frac{1}{2}\)
2
8
32
Explication
E = Er x E0
16 = Er x 2
Er = 8
16 = Er x 2
Er = 8