JAMB - Mathematics (2019 - No. 11)
If a fair coin is tossed 3 times, what is the probability of getting at least two heads?
\(\frac{2}{3}\)
\(\frac{4}{5}\)
\(\frac{2}{5}\)
\(\frac{1}{2}\)
Explication
The outcomes are {HHH, HHT, HTT, HTH, THH, THT, TTH, TTT}
P(at least two heads) = \(\frac{4}{8}\)
= \(\frac{1}{2}\)