JAMB - Mathematics (2012 - No. 1)
Convert 112\(_6\) to a number in base three
2211
2121
1212
1122
Explication
First, convert to base 10
112\(_6\) = (1 x 6\(^2\)) + (1 x 6\(^1\)) + (2 x 6\(^0\))
= 36 + 6 + 2
= 44\(_{10}\)
\(\begin{array}{c|c} 3 & 44 \\ \hline 3 & 14 & r 2 \\ \hline 3 & 4 & r 2 \\ \hline 3 & 1 & r 1 \\ \hline 3 & 0 & r 1 \end{array}\)
Ans = 1122 = D
112\(_6\) = (1 x 6\(^2\)) + (1 x 6\(^1\)) + (2 x 6\(^0\))
= 36 + 6 + 2
= 44\(_{10}\)
\(\begin{array}{c|c} 3 & 44 \\ \hline 3 & 14 & r 2 \\ \hline 3 & 4 & r 2 \\ \hline 3 & 1 & r 1 \\ \hline 3 & 0 & r 1 \end{array}\)
Ans = 1122 = D