JAMB - Mathematics (2010 - No. 17)

Find ∫(sin x + 2)dx

cos x + x² + K

cos x 2x + K

-cos x + x² + K

-cos x + 2x + K

Explication

∫(sin χ + 2)dχ = (∫sin χ + ∫2)dx
= -cos χ + 2χ + K

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