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JAMB - Mathematics (1994 - No. 19)

Find the nth term of the sequence 3, 6, 10, 15, 21.....
\(\frac{n(n - 1)}{2}\)
\(\frac{n(n + 1)}{2}\)
\(\frac{(n + 1)(n + 2)}{2}\)
n(2n + 1)

Explication

\(\frac{(n + 1)(n + 2)}{2}\)

If n = 1, the expression becomes 3

n = 2, the expression becomes 6

n = 4, the expression becomes 15

n = 5, the expression becomes 21

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