JAMB - Mathematics (1992 - No. 23)
If the angles of quadrilateral are (p + 10)°, (2p - 30)°, (3p + 20)° and 4p°, find p.
63
40
36
28
Explication
The sum of angles in a quadrilateral = 360°
\(\therefore (p + 10) + (2p - 30) + (3p + 20) + 4p = 360\)
\(10p = 360° \implies p = \frac{360}{10} = 36°\)