JAMB - Chemistry (2004 - No. 25)
The mass of silver deposited when a current of 10A is passed through a solution of silver salt for 4830s is
[Ag = 108, 1F = 96500 Cmol-1]
[Ag = 108, 1F = 96500 Cmol-1]
108.0g
54.0g
27.0g
13.5g
Explication
Ag\(^+\) + e\(^-\) → Ag
If 96500 C deposited 108g of Ag
∴ 10 x 4830C will deposit Xg of Ag
X = \(\frac{{108}\times{4830}\times{10}}{96500}\)
X = 54.06g