WAEC - Physics (2015 - No. 28)
A swimming pool is 2.1m deep. If it contains water of refractive index 1.3, calculate the apparent depth of pool
3.4m
2.7m
1.6m
0.8m
Selitys
n = \(\frac{\text{real depth}}{\text{apparent depth}}\)
1.3 = \(\frac{2.1}{\text{apparent}}\)
A.D = \(\frac{2.1}{1.3} = 1.6\)
1.3 = \(\frac{2.1}{\text{apparent}}\)
A.D = \(\frac{2.1}{1.3} = 1.6\)