WAEC - Physics (2012 - No. 37)
A 12\(\Omega\) resistor dissipates 8kJ of heat in 20s. Calculate the current through the resistor
5.8A
6.9A
30.0A
33.3A
Selitys
Q = I2Rt
I = \(\sqrt{\frac{Q}{Rt}}\)
= \(\sqrt{\frac{8000}{12 \times 20}}\)
= 5.8
I = \(\sqrt{\frac{Q}{Rt}}\)
= \(\sqrt{\frac{8000}{12 \times 20}}\)
= 5.8