WAEC - Physics (2011 - No. 28)
An object is placed 20.0cm in front of a converging lens of focal length 15.0cm. Calculate its image distance
1.3cm
8.6cm
35.0cm
60.0cm
Selitys
\(\frac{1}{v} = \frac{1}{f} - \frac{1}{U}\)
\(\frac{1}{15} - \frac{1}{20} = 60cm\)
\(\frac{1}{15} - \frac{1}{20} = 60cm\)