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WAEC - Physics (2010 - No. 36)

Use the diagram above to calculate the current, I.
0.60A
0.97A
1.03A
5.00A

Selitys

\(\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2}\)

= \(\frac{1}{6} + \frac{1}{4}\)

R = \(\frac{12}{5} = 2.5\Omega\)

R = 2.4 + 10 = 12.4

V = IR

I = \(\frac{v}{R} = \frac{12}{12.4} = 0.97\)

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