WAEC - Physics (2004 - No. 11)
A machine of velocity ratio 5 is used in lifting a load with an effort of 500N. If the machine is 80% efficient. Determine the magnitude of load
2500N
2000N
900N
625N
Selitys
M.A = \(\frac{Eff \times V.r}{100} = \frac{80 \times 5}{100} = 4\)
Load = effort x M.A
= 4 x 500 = 2000N
Load = effort x M.A
= 4 x 500 = 2000N