WAEC - Physics (2003 - No. 21)
The horizontal floor of a water reservoir appears to be 1.0m deep when viewed vertically from above. If the refractive index of water is 1.35, calculate the real depth of the reservoir
2.35m
1.35m
1.00m
0.35m
Selitys
n = \(\frac{R.d}{A.d}\)
1.35 = \(\frac{R.d}{1}\)
R.d = 1.35m
1.35 = \(\frac{R.d}{1}\)
R.d = 1.35m