WAEC - Physics (1993 - No. 6)
A body of mass m = 0.5 kg is suspended by a string and pulled by a horizontal force of 12N as shown in the diagram. Calculate the tension T in the String if the body is in equilibrium. [Take g as 10ms\(^{-1}\)]
7.0
10.9
12.5
13.0
17.0
Selitys
Mg = 5N
T\(_2\) = 5\(^2\) + 12\(^2\) = 13N