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WAEC - Physics (1993 - No. 24)

A man stands in front of a tall wall and produces a sound. If he receives the echo of the sound two seconds later, calculate his distance from the wall. (The speed of sound in air is 330ms-1)
600m
400m
330m
328m
165m

Selitys

x = vt/2 = \(\frac {330 \times 2} {2}\) = 660/2 = 330m

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