WAEC - Mathematics (2015 - No. 6)
Given that logx 64 = 3, evaluate x log\(_2\)8
6
9
12
24
Selitys
If logx 64 = 3, then \(64 = x^3\)
\(4^3 = x^3\)
Since the indices are equal,
x = 4
Hence, x log\(_2\)8
= 4(3.log\(_2\)2)
= where log\(_2\)2 = 1(1)
= 12 X 1
= 12