WAEC - Mathematics (2013 - No. 24)
The graph of the relation y = x2 + 2x + k passes through the point (2, 0). Find the values of k
zero
-2
-4
-8
Selitys
y = x2 + 2x + k at point(2,0) x = 2, y = 0
0 = (2)2 + 2(20 + k)
0 = 4 + 4 + k
0 = 8 + k
k = -8
0 = (2)2 + 2(20 + k)
0 = 4 + 4 + k
0 = 8 + k
k = -8