WAEC - Mathematics (2012 - No. 24)
If p = {prime factors of 210} and Q = {prime less than 10}, find p \(\cap\) Q
{1,2, 3}
{2, 3, 5}
{1, 3, 5,7}
{2,3,5,7}
Selitys
prime factor of 210 = 2, 3, 5, 7
prime numbers less than 10 = 2, 3, 5 , 7
prime numbers less than 10 = 2, 3, 5 , 7