WAEC - Mathematics (2009 - No. 9)
If (2x + 3)3 = 125, find the value of x
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Selitys
(2x + 3 )2 = 125
2n + 3 = 3\(\sqrt{125}\)
2x + 3 = 5
2x = 5 - 3
x = \(\frac{2}{2}\)
= 1
2n + 3 = 3\(\sqrt{125}\)
2x + 3 = 5
2x = 5 - 3
x = \(\frac{2}{2}\)
= 1