WAEC - Mathematics (2007 - No. 13)
If \(8^{x+1}=\frac{1}{4}\), find x
\(-\frac{5}{3}\)
-1
\(-\frac{1}{3}\)
\(\frac{1}{3}\)
Selitys
\(8^{x+1}=\frac{1}{4}\\
2^{3(x+1)}=2^{-2}\Rightarrow 3(x+1)=-2\Rightarrow 3x+3=-2\\
3x=-5\Rightarrow x = -\frac{5}{3}\)
2^{3(x+1)}=2^{-2}\Rightarrow 3(x+1)=-2\Rightarrow 3x+3=-2\\
3x=-5\Rightarrow x = -\frac{5}{3}\)