WAEC - Mathematics (2005 - No. 12)
Solve the equation 2\(^7\) = 8\(^{5-x}\)
\(\frac{5}{8}\)
\(\frac{8}{3}\)
\(\frac{3}{2}\)
\(\frac{15}{4}\)
Selitys
2\(^7\) = 8\(^{5-x}\)
2\(^7\) = 2\(^{3(5 - x)}\)
7 = 15 - 3x
7 - 15 = - 3x
-8 = -3x
x = \(\frac{8}{3}\)